AlgebraFoundationYear 8-10

Indices and the Laws of Exponents

Indices (powers) show repeated multiplication. The laws of indices let you multiply and divide powers with the same base by adding or subtracting their indices. Negative indices represent reciprocals and a zero index equals one, provided the base is not zero.

Dr. Pankaj Jha8 min readPublished 2026-08-28

Before you begin

You should be comfortable multiplying and dividing numbers and simplifying fractions.

The intuition

Writing a3a^3 means a×a×aa \times a \times a — three copies of aa multiplied together. The laws of indices are shortcuts that follow from this definition.

Definitions

  • Base: the number being raised to a power.
  • Index (exponent): the number of times the base is multiplied.
  • a0=1a^0 = 1 (for a≠0a \neq 0).
  • a−n=1ana^{-n} = \frac{1}{a^n}.
  • a1/n=ana^{1/n} = \sqrt[n]{a} (the nn-th root).

The laws of indices

  1. Multiplication: am×an=am+na^m \times a^n = a^{m+n}
  2. Division: am÷an=am−na^m \div a^n = a^{m-n}
  3. Power of a power: (am)n=amn(a^m)^n = a^{mn}
  4. Power of a product: (ab)n=anbn(ab)^n = a^n b^n
  5. Power of a quotient: (ab)n=anbn\left(\frac{a}{b}\right)^n = \frac{a^n}{b^n}
  6. Negative index: a−n=1ana^{-n} = \frac{1}{a^n}
  7. Fractional index: am/n=(an)ma^{m/n} = \left(\sqrt[n]{a}\right)^m

Step-by-step method

  1. Identify the base. The laws only apply when the base is the same.
  2. Decide which law matches the operation.
  3. Apply the law to combine or simplify the indices.
  4. Give the answer with a single index where possible.

Worked examples

Foundation example

Simplify x5×x3x^5 \times x^3. Same base, multiplication: add the indices. x5×x3=x5+3=x8x^5 \times x^3 = x^{5+3} = x^8

Developing example

Simplify 6a7b22a3b5\frac{6a^7 b^2}{2a^3 b^5} and write your answer with positive indices. Deal with numbers and each letter separately. 6a7b22a3b5=3⋅a7−3⋅b2−5=3a4b−3=3a4b3\frac{6a^7 b^2}{2a^3 b^5} = 3 \cdot a^{7-3} \cdot b^{2-5} = 3a^4 b^{-3} = \frac{3a^4}{b^3}

Advanced example

Simplify (2x−2)3×(x5)2\left(2x^{-2}\right)^3 \times \left(x^5\right)^2 with positive indices. (2x−2)3=23⋅x−6=8x−6\left(2x^{-2}\right)^3 = 2^3 \cdot x^{-6} = 8x^{-6} (x5)2=x10\left(x^5\right)^2 = x^{10} 8x−6×x10=8x−6+10=8x48x^{-6} \times x^{10} = 8x^{-6+10} = 8x^4

Common mistakes

  • Different bases: x3×y4x^3 \times y^4 cannot be simplified by adding indices.
  • Forgetting brackets: (2x)3=8x3(2x)^3 = 8x^3, not 2x32x^3.
  • Mixing up signs: a−na^{-n} is a reciprocal, not a negative number.

Concept checklist

  • I can apply each of the seven laws.
  • I can convert between negative and fractional indices.
  • I can simplify expressions with mixed indices.

Practice questions

  1. Simplify a4×a9a^4 \times a^9.
  2. Simplify x10x4\frac{x^{10}}{x^4}.
  3. Simplify (y3)5(y^3)^5.
  4. Evaluate 5−25^{-2}.
  5. Simplify 8x6y34x2y7\frac{8x^6 y^3}{4x^2 y^7} with positive indices.
  6. Simplify (3a−2)2×a5(3a^{-2})^2 \times a^5 with positive indices.

Challenge questions

  1. Simplify (2x3)4x5⋅x2\frac{(2x^3)^4}{x^5 \cdot x^2} with positive indices.
  2. Show that 16−3/4=1816^{-3/4} = \frac{1}{8}.

Frequently asked questions

What is a negative index? A negative index means the reciprocal of the positive power: a−n=1ana^{-n} = \frac{1}{a^n}.

Why is a0=1a^0 = 1? Using the division law, am÷am=am−m=a0a^m \div a^m = a^{m-m} = a^0. But amam=1\frac{a^m}{a^m} = 1, so a0=1a^0 = 1 (for a≠0a \neq 0).

  • Standard form and very large or small numbers
  • Exponential functions and logarithms
  • Understanding surds and simplifying radicals
Show worked solutions

Worked solutions

1. a4×a9=a13a^4 \times a^9 = a^{13}. 2. x10/x4=x6x^{10}/x^4 = x^6. 3. (y3)5=y15(y^3)^5 = y^{15}. 4. 5−2=1/52=1/255^{-2} = 1/5^2 = 1/25. 5. 8x6y34x2y7=2x4y−4=2x4y4\frac{8x^6 y^3}{4x^2 y^7} = 2x^4 y^{-4} = \frac{2x^4}{y^4}. 6. (3a−2)2×a5=9a−4×a5=9a(3a^{-2})^2 \times a^5 = 9a^{-4} \times a^5 = 9a.

Challenge 1. (2x3)4=24x12=16x12(2x^3)^4 = 2^4 x^{12} = 16x^{12}. Denominator: x5⋅x2=x7x^5 \cdot x^2 = x^7. So 16x12x7=16x5\frac{16x^{12}}{x^7} = 16x^5. Challenge 2. 16−3/4=(161/4)−3=2−3=1816^{-3/4} = \left(16^{1/4}\right)^{-3} = 2^{-3} = \frac{1}{8}.

Mathematically reviewed by Dr. Pankaj Jha

Last reviewed: 2026-08-28 · Date modified: 2026-08-28

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